python - comparing sorted lists -

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• why “return list.sort()” return none, not list? 6 answers

implement program requests 3 words (strings) user. program should print true if words entered in alphabetical order; otherwise nothing printed.

enter first word: bass enter second word: salmon enter third word: whitefish true 

since b > s > w, prints true

this have far:

firstwords=input("enter first word: ")  secondwords=input("enter second word: ")  thirdwords=input("enter third word: ")  word=[firstwords,secondwords,thirdwords]  print(word)  k=word.sort()  print(k) if (k==none):     print('true')  elif (word==k):     print("true") 

somehow cannot store value of word.sort() in k

you sorting word "in place" (i.e. sorts word directly, doesn't return sorted copy) word.sort(). doesn't return useful.

you use k=sorted(word) instead, returns sorted copy , doesn't affect word.